9. Water is added to two containers for 20 minutes. The equations below model the ounces ofwater, y, in each container after x minutes. At the time when the containers hold the sameamount of water, how much water do they hold?Container A: y=62x+48Container B: y=-2x2 +80x+120234 ounces482 ounces792 ounces920 ounces

Answer:792 ouncesStep-by-step explanation:At the time when the containers hold the same amount of water the value of y in the equations is the same,  so[tex]\large 62x+48=-2x^2+80x+120[/tex]Solve the quadratic equation:[tex]\large 62x+48=-2x^2+80x+120\Rightarrow 2x^2-80x-120+62x+48=0\\\\2x^2-18x-72=0\Rightarrow x=\frac{-(-18)\pm\sqrt{(-18)^2-4(2)(-72)}}{2*2}=\\\\=\frac{18\pm\sqrt{324+576}}{4}=\frac{18\pm\sqrt{900}}{4}=\frac{18\pm 30}{4}[/tex]Take only the positive solution since x is positive (minutes)[tex]\large x=\frac{18+30}{4}=\frac{48}{4}=12[/tex]Now, compute the amount of water y by replacing x = 12 in any of the two equations, for example in container A which is easier to calculatey = 62(12) + 48 = 792The correct answer is then 792 ounces